vbs如何实现base64解密脚本代码-创新互联

这篇文章主要介绍vbs如何实现base64解密脚本代码，文中介绍的非常详细，具有一定的参考价值，感兴趣的小伙伴们一定要看完！

代码如下:

Function fDecode(sStringToDecode)
'This function will decode a Base64 encoded string and returns the decoded string.
'This becomes usefull when attempting to hide passwords from prying eyes.
Const CharList = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
Dim iDataLength, sOutputString, iGroupInitialCharacter
sStringToDecode = Replace(Replace(Replace(sStringToDecode, vbCrLf, ""), vbTab, ""), " ", "")
iDataLength = Len(sStringToDecode)
If iDataLength Mod 4 <> 0 Then
fDecode = "Bad string passed to fDecode() function."
Exit Function
End If
For iGroupInitialCharacter = 1 To iDataLength Step 4
Dim iDataByteCount, iCharacterCounter, sCharacter, iData, iGroup, sPreliminaryOutString
iDataByteCount = 3
iGroup = 0
For iCharacterCounter = 0 To 3
sCharacter = Mid(sStringToDecode, iGroupInitialCharacter + iCharacterCounter, 1)
If sCharacter = "=" Then
iDataByteCount = iDataByteCount - 1
iData = 0
Else
iData = InStr(1, CharList, sCharacter, 0) - 1
If iData = -1 Then
fDecode = "Bad string passed to fDecode() function."
Exit Function
End If
End If
iGroup = 64 * iGroup + iData
Next
iGroup = Hex(iGroup)
iGroup = String(6 - Len(iGroup), "0") & iGroup
sPreliminaryOutString = Chr(CByte("&H" & Mid(iGroup, 1, 2))) & Chr(CByte("&H" & Mid(iGroup, 3, 2))) & Chr(CByte("&H" & Mid(iGroup, 5, 2)))
sOutputString = sOutputString & Left(sPreliminaryOutString, iDataByteCount)
Next
fDecode = sOutputString
End Function

base64 测试代码：

代码如下:

Function fDecode(sStringToDecode)
'This function will decode a Base64 encoded string and returns the decoded string.
'This becomes usefull when attempting to hide passwords from prying eyes.
Const CharList = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
Dim iDataLength, sOutputString, iGroupInitialCharacter
sStringToDecode = Replace(Replace(Replace(sStringToDecode, vbCrLf, ""), vbTab, ""), " ", "")
iDataLength = Len(sStringToDecode)
If iDataLength Mod 4 <> 0 Then
fDecode = "Bad string passed to fDecode() function."
Exit Function
End If
For iGroupInitialCharacter = 1 To iDataLength Step 4
Dim iDataByteCount, iCharacterCounter, sCharacter, iData, iGroup, sPreliminaryOutString
iDataByteCount = 3
iGroup = 0
For iCharacterCounter = 0 To 3
sCharacter = Mid(sStringToDecode, iGroupInitialCharacter + iCharacterCounter, 1)
If sCharacter = "=" Then
iDataByteCount = iDataByteCount - 1
iData = 0
Else
iData = InStr(1, CharList, sCharacter, 0) - 1
If iData = -1 Then
fDecode = "Bad string passed to fDecode() function."
Exit Function
End If
End If
iGroup = 64 * iGroup + iData
Next
iGroup = Hex(iGroup)
iGroup = String(6 - Len(iGroup), "0") & iGroup
sPreliminaryOutString = Chr(CByte("&H" & Mid(iGroup, 1, 2))) & Chr(CByte("&H" & Mid(iGroup, 3, 2))) & Chr(CByte("&H" & Mid(iGroup, 5, 2)))
sOutputString = sOutputString & Left(sPreliminaryOutString, iDataByteCount)
Next
fDecode = sOutputString
End Function
msgbox fDecode("d3d3LmpiNTEubmV0")

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